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Step 1 Solve for the vertex of the parabola The vertex of a parabola of the form {eq}y= x^2 bx c {/eq} is always given by {eq}\left (\dfrac {b} {2a},f (\dfrac {b} {2a})\right) {/eq} StepParabola Calculator This calculator will find either the equation of the parabola from the given parameters or the axis of symmetry, eccentricity, latus rectum, length of the latus rectum, focus, vertex, directrix, focal parameter, xintercepts, yintercepts of the entered parabola To graph a parabola, visit the parabola grapher (choose theKey Takeaways The graph of any quadratic equation y = a x 2 b x c, where a, b, and c are real numbers and a ≠ 0, is called a parabola; Understand How The Graph Of A Parabola Is Related To Its Quadratic Function College Algebra Graph parabola y=(x+2)^2+5

Solve This 10 Consider The Parabola Y X2 The Shaded Area Is 1 232 533 734 Physics Motion In A Straight Line Meritnation Com  AnswerX=hpThe directrix is x= 15 kendraBada kendraBada Mathematics Middle School answered Consider the parabola (y 1)2 = 2(x 1) Which equation is used to find the directrix? between y = 4x − x2 and y = x then subtract from the integral of the first (between a and b) the integral of the second (again, between a and b) Part 1 Points of intersection occurs when 4x −x2 = x This occurs when either x = 0 or x = 3 (we could, but don't actually need to calculate ya and yb) Consider the parabola y=x^2 the shaded area is